Solving Friction Problems

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The bottom carton pushes up against the top carton, and the top carton pushes down against the bottom one.

The gravitational force on the bottom carton is due to its mass only.

The coefficient of kinetic friction is usually lower than the one of static friction.

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As the truck brakes, each carton will continue to move forward at a constant velocity due to inertia unless there is a net force (such as friction) acting on it. The problem statement tells you that there is friction both between the bottom carton and the truck and between the two cartons.

Recall that friction acts to oppose sliding motion.It is true that the bottom carton feels the weight of the top carton.However, that information is transmitted through the force of contact, n.The problem statement tells you that there is friction both between the bottom carton and the truck and between the two cartons.I used the same symbol for this force (fr The two cartons press against each other.In other words, there is a normal force between the cartons.As understood through Newton’s Third Law, both cartons feel that interaction equally and so I used the same symbol for the force on both FBDs.As the truck slows down, the bottom carton wants to slide forward (continue at a constant velocity) so the friction that the truck puts on the bottom carton (fr) opposes a motion in which the top carton slides forward relative to the bottom (friction on the top carton is directed backwards) and the bottom carton slides backward with respect to the top (friction on the bottom carton is directed forward.) A good analogy for friction is Velcro—if the bottom tape pulls backward on the top tape, the top tape pulls forward on the bottom one.I used the same symbol for this force (fr) on both free body diagrams, because both cartons feel the strength of the interaction equally (Newton’s Third Law.) The gravitational force on the bottom carton is due to its mass only.Here y is the distance moved by the body down the plane. The coefficient of kinetic friction between the objects and incline is given by. 1/(1-n Question 5A uniform chain of length L is lying on the horizontal surface of a table. A force is applied to the body to make it just slide with a constant acceleration which is a. 3g/4 d g Solution 6 Minimum force with which body will just move=μmg or a=g/4 Question 7 A block of m Ass M is moving with a velocity v on straight surface.

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Comments Solving Friction Problems

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